[LeetCode] 158. Read N Characters Given Read4 II - Call multiple times
The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example ...
原文：[LeetCode] 158. Read N Characters Given Read4 II - Call multiple times 用Read4來讀取N個字符之二 - 多次調用
Given a file and assume that you can only read the file using a given methodread , implement a methodreadto readncharacters.Your methodreadmay be called multiple times. Method read : The APIread read ...
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[LeetCode] 157. Read N Characters Given Read4 用Read4來讀取N個字符
Given a file and assume that you can only read the file using a given method read4, implement a method to read n characters. Method read4 ...
Leetcode: Read N Characters Given Read4 II - Call multiple times
這道題跟I不一樣在於，read函數可能多次調用，比如read(buf,23)之后又read(buf, 25), 第一次調用時的buffer還沒用完，還剩一個char在buffer里，第二次拿出來接着用，這樣才能保證接着上次讀的地方繼續往下讀。 1. 所以應該設置這4個char ...
[leetcode]Read N Characters Given Read4 II - Call multiple times
leetcode上面寫的難度是hard，其實很簡單，前面也寫了，加個buffer就好了。 ...
[leetcode]Read N Characters Given Read4
用read4實現readn... 至調用一次，感覺怎么搞都可以。。。估計這個題有II就是調用多次了。。。 感覺多次勇哥buffer存下多讀的那部分就好了。。。 ...
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