Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. ...
Given an arraynumscontainingn integers where each integer is between andn inclusive , prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the dup ...
2015-09-28 11:37 18 35864 推薦指數:
Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. ...
287. 尋找重復數 這題的難點就在於下面的說明了,我們先不管下面的那些說明的要求,用常規的解法來解答下上的題目。 排序思想解法 先把原來的數組進行排序,然后逐個遍歷,一旦發現后一個元素和當前的元素相等,那么就返回,這就是我們找到了重復數字。但是這種思想,就不滿足說明里面的,不能改變原 ...
對於一個長度為n+1的數組,其中每一個值的取值范圍是[1,n],可以證明的是必然存在一個重復數字(抽屜原理),假設僅存在一個重復數字,找到他。 舉例:輸入:[1,3,4,2,1],輸出:1 自己做的時候,要么時間復雜度到o(n2),要么需要額外的存儲空間利用hashset,下面來分析一下 ...
Given a binary tree, return all duplicate subtrees. For each kind of duplicate subtrees, you only need to return the root node of any oneof ...
Given a list of directory info including directory path, and all the files with contents in this directory, you need to find out all the groups ...
letter at a random position. Find the letter that was a ...
Write a SQL query to find all duplicate emails in a table named Person. For example, your query should return the following for the above table ...
Given two strings representing two complex numbers. You need to return a string representing the ...