Leetcode: Partition List
思路: 1. 空間復雜度為 o(n) 解法. 創建兩個鏈表, 分別記錄大於 x 和小於 x 的節點, 最后合並 2. o(1) 的空間復雜度解法. 四個指針, 分別指向小於 x 部分鏈表的頭, 尾, 指向大於 x 部分鏈表的頭, 尾 總結: 1. 使用 dummyNode 減少判斷 ...
原文：[LeetCode] Partition List 划分鏈表
Given a linked list and a valuex, partition it such that all nodes less thanxcome before nodes greater than or equal tox. You should preserve the original relative order of the nodes in each of the t ...
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