Given a file and assume that you can only read the file using a given method read4, implement a method to read n characters. Method read4 ...
用read 實現readn... 至調用一次,感覺怎么搞都可以。。。估計這個題有II就是調用多次了。。。 感覺多次勇哥buffer存下多讀的那部分就好了。。。 ...
2014-11-21 23:28 4 1940 推薦指數:
Given a file and assume that you can only read the file using a given method read4, implement a method to read n characters. Method read4 ...
這道題跟I不一樣在於,read函數可能多次調用,比如read(buf,23)之后又read(buf, 25), 第一次調用時的buffer還沒用完,還剩一個char在buffer里,第二次拿出來接着用,這樣才能保證接着上次讀的地方繼續往下讀。 1. 所以應該設置這4個char ...
The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example ...
leetcode上面寫的難度是hard,其實很簡單,前面也寫了,加個buffer就好了。 ...
Given a file and assume that you can only read the file using a given method read4, implement a method read to read n characters. Your method read ...
We have a sorted set of digits `D`, a non-empty subset of `{'1','2','3','4','5','6','7','8','9'}`. ...
Let's define a function `countUniqueChars(s)` that returns the number of unique characters on `s`, for example if `s = "LEETCODE"` then `"L"`, `"T ...
ssize_t read(int fildes, void *buf, size_t nbyte); 返回值: > 0: 實際讀到的字節數 = 0: 讀完數據(讀文件, 管道, socket末尾-->對端關閉, 對端未關閉會一直等待) -1: 異常: errno ...