題目: 給出兩個排序的單鏈表,合並兩個單鏈表,返回合並后的結果; 解題思路: 解法還是很簡單的,但是需要注意以下幾點: 1. 如果兩個鏈表都空,則返回null; 2. 如果鏈表1空,則返回鏈表2的頭節點;反之,如果鏈表2為空,則返回鏈表1的頭節點; 3. 兩個鏈表都不空的情況下 ...
題目:Merge Two Sorted Lists 簡單題,只要對兩個鏈表中的元素進行比較,然后移動即可,只要對鏈表的增刪操作熟悉,幾分鍾就可以寫出來,代碼如下: 這其中要注意一點,即要記得處理一個鏈表為空,另一個不為空的情況,如 , gt ,當然上面的寫法多少啰嗦了一些,可以簡寫。 ...
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題目: 給出兩個排序的單鏈表,合並兩個單鏈表,返回合並后的結果; 解題思路: 解法還是很簡單的,但是需要注意以下幾點: 1. 如果兩個鏈表都空,則返回null; 2. 如果鏈表1空,則返回鏈表2的頭節點;反之,如果鏈表2為空,則返回鏈表1的頭節點; 3. 兩個鏈表都不空的情況下 ...
1. 題目描述 Merge two sorted linked lists and return it as a new sorted list. The new list should be made by splicing together the nodes of the first ...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists ...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 維護一個新 ...
題目: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists ...
原題地址:https://oj.leetcode.com/problems/merge-two-sorted-lists/ 題意:Merge two sorted linked lists and return it as a new list. The new list should ...
題目: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists ...
問題:有序合並兩個有序鏈表分析:歸並排序的合並部分 class Solution { public: ListNode *mergeTwoLists(ListNode *l1, ListNode *l2) { ListNode *helper=new ...