比如,在MySQL數據庫中,有數據表messages和數據記錄,如下:
mysql> select * from messages;
+----+------+-----------+
| id | name | data |
+----+------+-----------+
| 1 | A | A_data_1 |
| 2 | A | A_data_2 |
| 3 | A | A_data_3 |
| 4 | B | B_data_1 |
| 5 | B | B_data_2 |
| 6 | C | C_data_1 |
+----+------+-----------+
6 rows in set (0.00 sec)
方法一
select * from messages where id in (select max(id) from messages group by name);
方法二
select m1.* from messages m1 left join messages m2
on m1.name=m2.name and m1.id<m2.id
where m2.id is null;
方法二稍微難理解一點,但是只要把中間結果輸出出來,很快就可以理解了,如下:
select * from messages m1 left join messages m2
on m1.name=m2.name and m1.id<m2.id;
結果:
mysql> select * from messages m1 left join messages m2
-> on m1.name=m2.name and m1.id<m2.id;
+----+------+----------+------+------+----------+
| id | name | data | id | name | data |
+----+------+----------+------+------+----------+
| 1 | A | A_data_1 | 2 | A | A_data_2 |
| 1 | A | A_data_1 | 3 | A | A_data_3 |
| 2 | A | A_data_2 | 3 | A | A_data_3 |
| 3 | A | A_data_3 | NULL | NULL | NULL |
| 4 | B | B_data_1 | 5 | B | B_data_2 |
| 5 | B | B_data_2 | NULL | NULL | NULL |
| 6 | C | C_data_1 | NULL | NULL | NULL |
+----+------+----------+------+------+----------+
7 rows in set (0.00 sec)
可以看到id較大的進行左連接的時候,右側都是NULL,於是就可以找出ID最大的行。