C# 如何獲取屏幕分辨率縮放比例

獲取分辨率縮放比例：

 

 

        public const int HORZRES = 8;
        public const int VERTRES = 10;
        public const int LOGPIXELSX = 88;
        public const int LOGPIXELSY = 90;
        public const int DESKTOPVERTRES = 117;
        public const int DESKTOPHORZRES = 118;

        [DllImport("user32.dll")]
        public static extern IntPtr GetDC(IntPtr ptr);
        [DllImport("gdi32.dll")]
        public static extern int GetDeviceCaps(
            IntPtr hdc, // handle to DC
            int nIndex // index of capability
        );
        [DllImport("user32.dll", EntryPoint = "ReleaseDC")]
        public static extern IntPtr ReleaseDC(IntPtr hWnd, IntPtr hDc);
        [DllImport("user32.dll")]
        public static extern IntPtr GetDesktopWindow();

 

public static float GetSreenScale()
        {
            var hdc = Win32.GetDC(Win32.GetDesktopWindow());
            int nWidth = Win32.GetDeviceCaps(hdc, Win32.DESKTOPHORZRES);
            Win32.ReleaseDC(IntPtr.Zero, hdc);
            float f_Scale = (float)nWidth / (float)Screen.PrimaryScreen.Bounds.Width;
            return 1 / f_Scale;
        }