需求:
1、把如下數據按照parent_id等於id的規則建立父子關系
2、同一層級的數組按照order升序
[ { "id": 1, "name": "estate", "title": "物業管理", "type": "nav", "leave": 1, "order": 1, "parent_id": 0, "url": "/estate" },
{ "id": 2, "name": "house", "title": "費用管理", "type": "nav", "leave": 2, "order": 1, "parent_id": 1, "url": "estate" },
{ "id": 3, "name": "temporaryCharges", "title": "臨時收費", "type": "nav", "leave": 3, "order": 1, "parent_id": 2, "url": "charge" },
{ "id": 4, "name": "propertyFees", "title": "物業費", "type": "nav", "leave": 3, "order": 2, "parent_id": 2, "url": "propertyFees" },
{ "id": 6, "name": "propertyFeesEdit", "title": "編輯", "type": "handle", "leave": 4, "order": 2, "parent_id": 4, "url": null },
{ "id": 7, "name": "propertyFeesLogs", "title": "記錄", "type": "handle", "leave": 4, "order": 3, "parent_id": 4, "url": null },
{ "id": 8, "name": "propertyFeesPayment", "title": "繳費", "type": "handle", "leave": 4, "order": 4, "parent_id": 4, "url": null },
{ "id": 9, "name": "carFees", "title": "停車費", "type": "nav", "leave": 3, "order": 3, "parent_id": 2, "url": "carFees" },
{ "id": 11, "name": "carFeesLogs", "title": "記錄", "type": "handle", "leave": 4, "order": 2, "parent_id": 9, "url": null },
{ "id": 12, "name": "carFeesPayment", "title": "繳費", "type": "handle", "leave": 4, "order": 3, "parent_id": 9, "url": null },
{ "id": 13, "name": "gain", "title": "固定收益", "type": "nav", "leave": 3, "order": 4, "parent_id": 2, "url": "gain" },
{ "id": 14, "name": "bill", "title": "賬單管理", "type": "nav", "leave": 2, "order": 2, "parent_id": 1, "url": "estate" },
......]
最終效果:
[{
"id": 1,
"name": "estate",
"title": "物業管理",
"type": "nav",
"leave": 1,
"order": 1,
"parent_id": 0,
"url": "/estate",
"children": [{
"id": 2,
"name": "house",
"title": "費用管理",
"type": "nav",
"leave": 2,
"order": 1,
"parent_id": 1,
"url": "estate",
"children": [{
"id": 3,
"name": "temporaryCharges",
"title": "臨時收費",
"type": "nav",
"leave": 3,
"order": 1,
"parent_id": 2,
"url": "charge"
}, {
"id": 4,
"name": "propertyFees",
"title": "物業費",
"type": "nav",
"leave": 3,
"order": 2,
"parent_id": 2,
"url": "propertyFees",
"children": [{
"id": 6,
"name": "propertyFeesEdit",
"title": "編輯",
"type": "handle",
"leave": 4,
"order": 2,
"parent_id": 4,
"url": null
}, {
"id": 7,
"name": "propertyFeesLogs",
"title": "記錄",
"type": "handle",
"leave": 4,
"order": 3,
"parent_id": 4,
"url": null
}
.......
}
}]
實現代碼:
'use strict';
exports.formatRouter = {
/**
* 樹形數據格式化,其中:
* 子級的’parent_id‘等於父級的id,
* 最高父級的id為0
*
* 排序規則為‘order’的數字順序
* */
treeData(data) {
// 對源數據深度克隆
const cloneData = JSON.parse(JSON.stringify(data));
// filter嵌套filter相當於for循環嵌套for循環
const result = cloneData.filter(parent => {
// 返回每一項的子級數組
const branchArr = cloneData.filter(child => parent.id === child.parent_id);
// 若子級存在,則給子級排序;且,賦值給父級
if (branchArr.length > 0) {
branchArr.sort(this.compare('order'));
parent.children = branchArr;
}
// 返回最高的父級,即,parent_id為0,
return parent.parent_id === 0;
});
// 給最高級的父級排序
result.sort(this.compare('order'));
return result;
},
// 對象數組排序
compare(property) {
return function(a, b) {
const value1 = a[property];
const value2 = b[property];
return value1 - value2;// 升序,降序為value2 - value1
};
},
};
說明:
其實就是兩個for循環嵌套,性能上還沒有for循環好。