關於Java8的stream流,這里不講groupBy分組,也不講sort排序,這些都是很基礎的用法,可以自行百度。
這里說一種業務場景,對於分組后的map,根據value對key-value進行排序。舉個例子,人(姓名,地址,創建時間)的集合,要求按地址將他們分組,同時要求越晚被創建的人,所在的分組越靠前。
直接上People類:
import lombok.AllArgsConstructor;
import lombok.Data;
@Data
@AllArgsConstructor
public class People {
private String name;
private String address;
private Long createTime;
}
然后是分組排序代碼:
public static void main(String[] args) {
long time = 1L;
List<People> list = new ArrayList<>();
list.add(new People("曹丕", "魏", time++));
list.add(new People("關羽", "蜀", time++));
list.add(new People("劉備", "蜀", time++));
list.add(new People("小喬", "吳", time++));
list.add(new People("周瑜", "吳", time++));
list.add(new People("曹操", "魏", time++));
Map<String, List<People>> collect = list.stream()
.filter(d -> d != null && d.getAddress() != null) // 這里是為了下面分組的key不為null,要是key為null會報錯的
.sorted(Comparator.comparingLong(People::getCreateTime).reversed())
.collect(Collectors.groupingBy(People::getAddress, LinkedHashMap::new, Collectors.toList()));
for (Map.Entry<String, List<People>> entry : collect.entrySet()) {
System.out.println(entry.getKey() + "\t" + entry.getValue());
}
}
最后是運行結果:
魏 [People(name=曹操, address=魏, createTime=6), People(name=曹丕, address=魏, createTime=1)]
吳 [People(name=周瑜, address=吳, createTime=5), People(name=小喬, address=吳, createTime=4)]
蜀 [People(name=劉備, address=蜀, createTime=3), People(name=關羽, address=蜀, createTime=2)]
那么如果按照題目要求,這個時候,我再加個“蜀國”人,那么這個人所在分組就應該放到第一的位置
long time = 1L;
List<People> list = new ArrayList<>();
list.add(new People("曹丕", "魏", time++));
list.add(new People("關羽", "蜀", time++));
list.add(new People("劉備", "蜀", time++));
list.add(new People("小喬", "吳", time++));
list.add(new People("周瑜", "吳", time++));
list.add(new People("曹操", "魏", time++));
list.add(new People("張飛", "蜀", time++));
運行后結果如下,發現最后添加的“張飛”所在的“蜀”分類,已經放到了第一的位置:
蜀 [People(name=張飛, address=蜀, createTime=7), People(name=劉備, address=蜀, createTime=3), People(name=關羽, address=蜀, createTime=2)]
魏 [People(name=曹操, address=魏, createTime=6), People(name=曹丕, address=魏, createTime=1)]
吳 [People(name=周瑜, address=吳, createTime=5), People(name=小喬, address=吳, createTime=4)]