刷題筆記-喊7的次數重排（簡單）python實現

str1=input()
str1=str1.split(' ')
#print(str1)
num=len(str1)
count=0
for i in str1:
    count=count+int(i)
count2=0
mn=[]
for i in range(num):
    mn.append(0)
for i in range(200):
    if  str(i).find('7')!=-1 or (i%7==0 and i!=0):
        count2=count2+1
        flag=i%num-1
        mn[flag]=mn[flag]+1
    #print(count2)
    if count2==count:
        break
for i in range(len(mn)):#避免多輸出一個空格
    if i ==len(mn)-1:
        print(mn[i])
    else:
        print(mn[i],end=" ")

輸入：0 0 0 2 1

輸出：0 2 0 1 0