前言:以前都是使用QueryWrapper的情況多一點,其余三種也沒怎么涉及。最近是因為優化一個項目,所以才突然想起。
首先准備一個對應的實體類:
@Data
@TableName("house")
public class HouseEntity {
@TableId(type = IdType.AUTO)
private Integer houseId;
private String houseOwner;
private String houseArea;
}
分別測試使用代碼測試,都以查詢所有的數據為目的。都注入
@Autowired
private HouseMapper houseMapper;
- QueryWrapper
@Test
public void test1() {
List<HouseEntity> list=houseMapper.selectList(new QueryWrapper<HouseEntity>()
.orderByDesc("house_area"));
System.out.println("QueryWrapper:"+list);
}
執行結果:QueryWrapper:[HouseEntity(houseId=2, houseOwner=LS, houseArea=72), HouseEntity(houseId=1, houseOwner=ZS, houseArea=70)]
- QueryChainWrapper
@Test
public void test() {
List<HouseEntity> list2=new QueryChainWrapper<>(houseMapper)
.orderByDesc("house_area").list();
System.out.println("QueryChainWrapper:"+list);
}
執行結果:QueryChainWrapper:[HouseEntity(houseId=2, houseOwner=LS, houseArea=72), HouseEntity(houseId=1, houseOwner=ZS, houseArea=70)]
- LambdaQueryWrapper
@Test
public void test3() {
List<HouseEntity> list=houseMapper.selectList(new LambdaQueryWrapper<HouseEntity>()
.orderByDesc(HouseEntity::getHouseArea));
System.out.println("LambdaQueryWrapper:"+list);
}
執行結果:LambdaQueryWrapper:[HouseEntity(houseId=2, houseOwner=LS, houseArea=72), HouseEntity(houseId=1, houseOwner=ZS, houseArea=70)]
- LambdaQueryChainWrapper
@Test
public void test3() {
List<HouseEntity> list = new LambdaQueryChainWrapper<>(houseMapper)
.orderByDesc(HouseEntity::getHouseArea).list();
System.out.println("LambdaQueryChainWrapper:"+list);
}
執行結果:LambdaQueryChainWrapper:[HouseEntity(houseId=2, houseOwner=LS, houseArea=72), HouseEntity(houseId=1, houseOwner=ZS, houseArea=70)]
總結:
QueryWrapper、QueryChainWrapper只能都只能指定需要的數據庫列名LambdaQueryWrapper、LambdaQueryChainWrapper可以通過獲取Lambda數據庫列名QueryWrapper、LambdaQueryWrapper不能使用鏈式查詢的方式,必須借助BaseMapper來執行QueryChainWrapper、LambdaQueryChainWrapper可以使用鏈式查詢的方式,如list(),one()
