SQL查詢兩個表相同的兩個字段里不同的數據有哪些

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select * from A

inner join B on A.Name = B.Name and A.ID = B.ID

where A.Name = '張三' and A.ID = '008'

內連接即可

或者：

1、除重

select distinct A.ID AS AID,A.Name AS AName,B.ID AS BID,B.Name AS BName from A inner join B on(A.Name=B.Name and A.ID=B.ID)

2、除重

select A.ID AS AID,A.Name AS AName,B.ID AS BID,B.Name AS BName from A inner join B on(A.Name=B.Name and A.ID=B.ID)

擴展資料：

SQL的其他查詢

1、查找表中多余的重復記錄，重復記錄是根據單個字段（peopleId）來判斷

select * from peoplewhere peopleId in (select peopleId from people group by peopleId 

having count(peopleId) > 1)

2、刪除表中多余的重復記錄，重復記錄是根據單個字段（peopleId）來判斷，只留有rowid最小的記錄

delete from peoplewhere peopleId in (select peopleId from people group by peopleId   

having count(peopleId) > 1)and rowid not in (select min(rowid) from people group by 

peopleId having count(peopleId )>1)

3、查找表中多余的重復記錄（多個字段）

select * from vitae awhere (a.peopleId,a.seq) in (select peopleId,seq from vitae group by 

peopleId,seq having count(*) > 1)

4、刪除表中多余的重復記錄（多個字段），只留有rowid最小的記錄

delete from vitae awhere (a.peopleId,a.seq) in (select peopleId,seq from vitae group by 

peopleId,seq having count(*) > 1)and rowid not in (select min(rowid) from vitae group by 

peopleId,seq having count(*)>1)

5、查找表中多余的重復記錄（多個字段），不包含rowid最小的記錄

select * from vitae awhere (a.peopleId,a.seq) in (select peopleId,seq from vitae group by 

peopleId,seq having count(*) > 1)and rowid not in (select min(rowid) from vitae group by 

peopleId,seq having count(*)>1)