>>> a = ["aa","bb","aa","cc","aa","dd","bb","aa","cc"] >>> a ['aa', 'bb', 'aa', 'cc', 'aa', 'dd', 'bb', 'aa', 'cc'] >>> b = a.count("aa") >>> b 4
>>> c = -1
>>> for i in range(b): c = a.index("aa",c + 1,len(a)) print("aa",c) aa 0 aa 2 aa 4 aa 7
python中輸出列表中重復元素的所有索引
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