1 //將一個字符串數組的元素的順序進行反轉。 2 3 //{“A”,“B”,”C”,"D","E","F"} {“F”,”E”,”D”,“C”,“B”,”A”}。第i個和第length-i-1個進行交換。 4 5 //i Length-1-0 6 7 //i+1 Leng-1-1 8 9 //i+2 Leng-1-2 10 11 12 13 string[] names = { "a", "b", "c", "d", "e", "f", "g" }; 14 for (int i = 0; i < names.Length / 2; i++) 15 { 16 string temp = names[i]; 17 names[i] = names[names.Length - 1 - i]; 18 names[names.Length - 1 - i] = temp; 19 } 20 21 for (int i = 0; i < names.Length; i++) 22 { 23 Console.WriteLine(names[i]); 24 } 25 Console.ReadKey(); 26 27
