python筆記53-Leetcode面試題:請實現一個函數，把字符串 s 中的每個空格替換成"%20"

前言

Leetcode上有個練習題，也是面試經常會遇到的：請實現一個函數，把字符串 s 中的每個空格替換成"%20"

替換字符串

請實現一個函數，把字符串 s 中的每個空格替換成"%20"
輸入：s = "We are happy."
輸出："We%20are%20happy."

'''
請實現一個函數，把字符串 s 中的每個空格替換成"%20"。
輸入：s = "We are happy."
輸出："We%20are%20happy."
'''
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def replaceSpace(s: str) ->str:                  
    '''把字符串 s 中的每個空格替換成"%20"'''
    res = ''
    for i in s:
        if i != " ":
            res += i
        else:
            res += "%20"
    return res
if __name__ == '__main__':
    s = "We are happy."
    print(replaceSpace(s))

解決思路就是遍歷字符串，判斷為空格就替換為%20

replace方法

python里面有個replace方法可以直接替換字符串

s = "We are happy."
print(s.replace(" ", "%20"))