"mappings": { "player": { "properties": { "name": { "index": "not_analyzed", "type": "string" }, "age": { "type": "integer" }, "salary": { "type": "integer" }, "team": { "index": "not_analyzed", "type": "string" }, "position": { "index": "not_analyzed", "type": "string" } }, "_all": { "enabled": false } } }
索引中的全部數據:
首先,初始化Builder:
SearchRequestBuilder sbuilder = client.prepareSearch("player").setTypes("player");
接下來舉例說明各種聚合操作的實現方法,因為在es的api中,多字段上的聚合操作需要用到子聚合(subAggregation),初學者可能找不到方法(網上資料比較少,筆者在這個問題上折騰了兩天,最后度了源碼才徹底搞清楚T_T),后邊會特意說明多字段聚合的實現方法。另外,聚合后的排序也會單獨說明。
- group by/count
例如要計算每個球隊的球員數,如果使用SQL語句,應表達如下:
select team, count(*) as player_count from player group by team;
ES的java api:
TermsBuilder teamAgg= AggregationBuilders.terms("player_count ").field("team");
sbuilder.addAggregation(teamAgg);
SearchResponse response = sbuilder.execute().actionGet();
- group by多個field
例如要計算每個球隊每個位置的球員數,如果使用SQL語句,應表達如下:
select team, position, count(*) as pos_count from player group by team, position;
TermsBuilder teamAgg= AggregationBuilders.terms("player_count ").field("team"); TermsBuilder posAgg= AggregationBuilders.terms("pos_count").field("position"); sbuilder.addAggregation(teamAgg.subAggregation(posAgg)); SearchResponse response = sbuilder.execute().actionGet();
- max/min/sum/avg
例如要計算每個球隊年齡最大/最小/總/平均的球員年齡,如果使用SQL語句,應表達如下:
select team, max(age) as max_age from player group by team;
ES的java api:
TermsBuilder teamAgg= AggregationBuilders.terms("player_count ").field("team"); MaxBuilder ageAgg= AggregationBuilders.max("max_age").field("age"); sbuilder.addAggregation(teamAgg.subAggregation(ageAgg)); SearchResponse response = sbuilder.execute().actionGet();
- 對多個field求max/min/sum/avg
例如要計算每個球隊球員的平均年齡,同時又要計算總年薪,如果使用SQL語句,應表達如下:
select team, avg(age)as avg_age, sum(salary) as total_salary from player group by team;
ES的java api:
TermsBuilder teamAgg= AggregationBuilders.terms("team"); AvgBuilder ageAgg= AggregationBuilders.avg("avg_age").field("age"); SumBuilder salaryAgg= AggregationBuilders.avg("total_salary ").field("salary"); sbuilder.addAggregation(teamAgg.subAggregation(ageAgg).subAggregation(salaryAgg)); SearchResponse response = sbuilder.execute().actionGet();
- 聚合后對Aggregation結果排序
例如要計算每個球隊總年薪,並按照總年薪倒序排列,如果使用SQL語句,應表達如下:
select team, sum(salary) as total_salary from player group by team order by total_salary desc;
ES的java api:
TermsBuilder teamAgg= AggregationBuilders.terms("team").order(Order.aggregation("total_salary ", false); SumBuilder salaryAgg= AggregationBuilders.avg("total_salary ").field("salary"); sbuilder.addAggregation(teamAgg.subAggregation(salaryAgg)); SearchResponse response = sbuilder.execute().actionGet();
需要特別注意的是,排序是在TermAggregation處執行的,Order.aggregation函數的第一個參數是aggregation的名字,第二個參數是boolean型,true表示正序,false表示倒序。
- Aggregation結果條數的問題
默認情況下,search執行后,僅返回10條聚合結果,如果想反悔更多的結果,需要在構建TermsBuilder 時指定size:
TermsBuilder teamAgg= AggregationBuilders.terms("team").size(15);
- Aggregation結果的解析/輸出
得到response后:
Map<String, Aggregation> aggMap = response.getAggregations().asMap(); StringTerms teamAgg= (StringTerms) aggMap.get("keywordAgg"); Iterator<Bucket> teamBucketIt = teamAgg.getBuckets().iterator(); while (teamBucketIt .hasNext()) { Bucket buck = teamBucketIt .next(); //球隊名 String team = buck.getKey(); //記錄數 long count = buck.getDocCount(); //得到所有子聚合 Map subaggmap = buck.getAggregations().asMap(); //avg值獲取方法 double avg_age= ((InternalAvg) subaggmap.get("avg_age")).getValue(); //sum值獲取方法 double total_salary = ((InternalSum) subaggmap.get("total_salary")).getValue(); //... //max/min以此類推 }
- 總結
綜上,聚合操作主要是調用了SearchRequestBuilder的addAggregation方法,通常是傳入一個TermsBuilder,子聚合調用TermsBuilder的subAggregation方法,可以添加的子聚合有TermsBuilder、SumBuilder、AvgBuilder、MaxBuilder、MinBuilder等常見的聚合操作。
從實現上來講,SearchRequestBuilder在內部保持了一個私有的 SearchSourceBuilder實例, SearchSourceBuilder內部包含一個List<AbstractAggregationBuilder>,每次調用addAggregation時會調用 SearchSourceBuilder實例,添加一個AggregationBuilder。
同樣的,TermsBuilder也在內部保持了一個List<AbstractAggregationBuilder>,調用addAggregation方法(來自父類addAggregation)時會添加一個AggregationBuilder。有興趣的讀者也可以閱讀源碼的實現。