jq判斷是否點擊返回，回到上一頁

<script>
      window.addEventListener('pageshow', function (event) {
           if(event.persisted || window.performance && window.performance.navigation.type == 2){        // 返回2則是點擊返回
               console.log('window.performance.navigation.type: '+ window.performance.navigation.type)
               // location.refresh();   //此處可以寫你的實際應用的代碼
           }
       },false);
</script>