構造list集合
List<Map<String,Object>> list = Lists.newArrayList();
IntStream.range(1,5).forEach(e->{
Map<String,Object> map = Maps.newHashMap();
map.put("name","張三"+(e<3?e:e-1));
map.put("score", (int)(Math.random()*100)+1);
list.add(map);
});
System.out.println(list);
輸出:[{score=60, name=張三1}, {score=94, name=張三2}, {score=75, name=張三2}, {score=55, name=張三3}]
根據map中的score進行過濾
//過濾分數大於60的元素
List<Map<String, Object>> filterList = list.stream().filter(
e -> (int) e.get("score") > 60).collect(Collectors.toList());
System.out.println(filterList);
輸出:[{score=94, name=張三2}, {score=75, name=張三2}]
根據map中的score進行排序
List<Map<String, Object>> sortList = list.stream().sorted((v1, v2) -> {
BigInteger b1 = new BigInteger(v1.get("score").toString());
BigInteger b2 = new BigInteger(v2.get("score").toString());
return b1.compareTo(b2);
}).collect(Collectors.toList());
System.out.println(sortList);
輸出:[{score=55, name=張三3}, {score=60, name=張三1}, {score=75, name=張三2}, {score=94, name=張三2}]
對集合中的map的value值求和
//通過Collect方式
int score = list.stream().collect(Collectors.summingInt(
e -> Integer.parseInt(e.get("score").toString())));
//通過map方式
int sum = list.stream().mapToInt(e -> Integer.parseInt(e.get("score").toString())).sum();
System.out.println(sum);
輸出:284
根據map的name進行分組,並將name相同的score值求和
List<Map<String, Object>> collectList = list.stream().collect(
Collectors.groupingBy(e -> e.get("name"))).values().stream().map(e -> {
Map<String, Object> map = e.get(0);
map.put("score", e.stream().map(
s -> new BigInteger(s.get("score").toString())).reduce(BigInteger.ZERO, BigInteger::add));
return map;
}).collect(Collectors.toList());
System.out.println(collectList);
輸出:[{score=55, name=張三3}, {score=60, name=張三1}, {score=169, name=張三2}]