SELECT n.pk_id, count( DISTINCT r.user_id ) forwardNum FROM news_info n INNER JOIN news_info_record r ON r.type = 1 AND r.news_id = n.pk_id AND r.data_active = 0 AND n.data_active = 0 GROUP BY r.news_id
按照news_id分組統計,但是在user_id相同的時候不能統計在內
SELECT n.pk_id, count( DISTINCT r.user_id ) forwardNum FROM news_info n INNER JOIN news_info_record r ON r.type = 1 AND r.news_id = n.pk_id AND r.data_active = 0 AND n.data_active = 0 GROUP BY r.news_id
按照news_id分組統計,但是在user_id相同的時候不能統計在內
本站轉載的文章為個人學習借鑒使用,本站對版權不負任何法律責任。如果侵犯了您的隱私權益,請聯系本站郵箱yoyou2525@163.com刪除。