go IP地址轉化為二進制數


原文鏈接:

https://studygolang.com/articles/11612

https://blog.csdn.net/yzf279533105/article/details/81238758

package main

import (
        "fmt"
        "strconv"
        "strings"
)

/* IP地址轉化為二進制數 */
func main() {
        addrInt := ipAddrToInt("192.168.8.152")

        /* 十進制轉化為二進制 */
        c := strconv.FormatInt(addrInt, 2)
        fmt.Println("c:", c)

        /* 二進制轉化為十進制 */
        d, err := strconv.ParseInt(c, 2, 64)
        fmt.Println("d:", d, err)
}

func ipAddrToInt(ipAddr string) int64 {
        bits := strings.Split(ipAddr, ".")
        b0, _ := strconv.Atoi(bits[0])
        b1, _ := strconv.Atoi(bits[1])
        b2, _ := strconv.Atoi(bits[2])
        b3, _ := strconv.Atoi(bits[3])
        var sum int64
        sum += int64(b0) << 24
        sum += int64(b1) << 16
        sum += int64(b2) << 8
        sum += int64(b3)

        return sum
}
func UInt32ToIP(intIP uint32) net.IP {
    var bytes [4]byte
    bytes[0] = byte(intIP & 0xFF)
    bytes[1] = byte((intIP >> 8) & 0xFF)
    bytes[2] = byte((intIP >> 16) & 0xFF)
    bytes[3] = byte((intIP >> 24) & 0xFF)
 
    return net.IPv4(bytes[3], bytes[2], bytes[1], bytes[0])
}

  

  


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