java8如何對list中的map元素根據一個key值進行排序

public static void main(String[] args) {
        Map<String, Object> map = new HashMap<String, Object>();
        map.put("name", "ZK");
        map.put("age", 13);

        Map<String, Object> map2 = new HashMap<String, Object>();
        map2.put("name", "ZA");
        map2.put("age", 15);

        Map<String, Object> map3 = new HashMap<String, Object>();
        map3.put("name", "CX");
        map3.put("age", 20);

        Map<String, Object> map4 = new HashMap<String, Object>();
        map4.put("name", "CX");
        map4.put("age", 18);

        List<Map<String, Object>> list = new ArrayList<Map<String,Object>>();
        list.add(map);
        list.add(map2);
        list.add(map3);
        list.add(map4);

如上的代碼排序方式為

 List<Map<String, Object>> collect =
  list.stream().sorted(Comparator.comparing(Test::comparingByName)
 .thenComparing(Comparator.comparing(Test::comparingByAge).reversed()))
                                                     .collect(Collectors.toList());

其中Test為你的類名.comparingByName和comparingByAge則是兩個方法

private static String comparingByName(Map<String, Object> map){
        return (String) map.get("name");
    }

    private static Integer comparingByAge(Map<String, Object> map){
        return (Integer) map.get("age");
    }

借助這兩個方法,取出map的參數進行對比