力扣-數組「動態和」的計算公式為：runningSum[i] = sum(nums[0]…nums[i])

class Solution {
    public int[] runningSum(int[] nums) {
        int i,j,temp=0;
        int[] rtnums=new int[nums.length];
        for(i=0;i<nums.length;i++){
            for(j=0;j<=i;j++){
                temp=temp+nums[j];
            }
            rtnums[i]=temp;
            temp=0;
        }
        return rtnums;
    }
}