解決方法之一:使用實體屬性類型轉換器AttributeConverter
場景假設:在代碼中使用枚舉類來映射用戶性別(如下代碼所示),在數據庫中使用字符映射性別(M ,F),Hibernate提供了AttributeConverter解決上述場景的轉換問題
public enum Gender {
MALE( 'M' ),
FEMALE( 'F' );
private final char code;
Gender(char code) {
this.code = code;
}
public static Gender fromCode(char code) {
if ( code == 'M' || code == 'm' ) {
return MALE;
}
if ( code == 'F' || code == 'f' ) {
return FEMALE;
}
throw new UnsupportedOperationException(
"The code " + code + " is not supported!"
);
}
public char getCode() {
return code;
}
}
User實體類定義如下,重點在 @Convert(converter = GenderConverter.class)注釋
@Entity
@Data
@ToString
@Table(name = "user")
public class User {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Integer id;
private String name;
@Convert(converter = GenderConverter.class)
private Gender gender;
}
定義一個GenderConverter的類,需要實現AttributeConverter接口,實現convertToDatabaseColumn和convertToEntityAttribute,作用是分別封裝從實體類映射至數據庫字段數值的邏輯和從數據庫字段數值映射到代碼實體類中的枚舉類值。
public class GenderConverter implements AttributeConverter<Gender,Character> {
@Override
public Character convertToDatabaseColumn(Gender gender) {
if ( gender == null ) {
return null;
}
return gender.getCode();
}
@Override
public Gender convertToEntityAttribute(Character value) {
if ( value == null ) {
return null;
}
return Gender.fromCode( value );
}
}
測試
@SpringBootTest
@Slf4j
public class AttributeConverterTest {
@Resource
private UserRepository userRepository;
@Test
void should_user__when__give_user() {
//given
User user1 = new User(null,"Janny", Gender.FEMALE);
User user2 = new User(null,"Tom", Gender.MALE);
//when
User actUser1 = userRepository.save(user1);
User actUser2 = userRepository.save(user2);
//then
Assertions.assertNotNull(actUser1);
Assertions.assertNotNull(actUser2);
}
}

例外Hibernate也提供其他的方法,如使用@Enumerated注解,詳情可閱讀下面文檔
文檔:https://docs.jboss.org/hibernate/stable/orm/userguide/html_single/Hibernate_User_Guide.html
