SpringBoot獲取前端傳遞JSON的幾種方法


一、Json對象+@RequestBody接收

var val = {id: 1, name: "小明"};
$.ajax({
    url: "/getJson",
    dataType: "JSON",
    type: "post",
    contentType: 'application/json;charset=UTF-8',
    data: JSON.stringify(val),
    success: function (msg) {
        console.log(msg)
    }
})

后端獲取參數:Map<String,Object>

@PostMapping("/getJson")
@ResponseBody
public Map<String,Object> getJsonVal(@RequestBody Map<String,Object> user) {
    System.out.println("user = " + user.get("id"));
    System.out.println("user = " + user.get("name"));
    return user;
}

后端獲取參數:對象

@PostMapping("/getJson")
@ResponseBody
public User getJsonVal(@RequestBody User user) {
    return user;
}

二、傳JSON對象

var val = {"id": 1, "name": "小明"};
$.ajax({
    url: "/getJson",
    dataType: "JSON",
    type: "post",
    // contentType: 'application/json;charset=UTF-8', //不能加
    data: val,
    success: function (msg) {
        console.log(msg)
    }
})

后端獲取參數

@PostMapping("/getJson")
@ResponseBody
public User getJsonVal(@RequestParam("id") String id,@RequestParam("name") String name) {
    User user = new User();
    user.setId(Integer.parseInt(id));
    user.setName(name);
    return user;
}

三、json集合+@RequestBody接收

var val = [{"id": 1, "name": "小明"},{"id": 2, "name": "小紅"}];
$.ajax({
    url: "/getJson",
    dataType: "JSON",
    type: "post",
    contentType: 'application/json;charset=UTF-8', //不能加
    data: JSON.stringify(val),
    success: function (msg) {
        console.log(msg)
    }
})

后端獲取參數

@PostMapping("/getJson")
@ResponseBody
public List<User> getJsonVal(@RequestBody List<User> user) throws IOException {
    for(User user2 : user){
        System.out.println("user2 = " + user2);
    }
    return user;
}

 


免責聲明!

本站轉載的文章為個人學習借鑒使用,本站對版權不負任何法律責任。如果侵犯了您的隱私權益,請聯系本站郵箱yoyou2525@163.com刪除。



 
粵ICP備18138465號   © 2018-2025 CODEPRJ.COM