php通過curl傳輸JSON對象

PHP通過curl方式傳參給java接口報錯：JSONObject["xxx"] is not a JSONObject

PHP 對變量進行 JSON 編碼 (json_encode()) 返回字符串，而接口參數需要 json 對象。

{"code":0,"data":{"isSrvAccount":0},"mccode":0,"errObj":{},"reqId":"S1B6Mt01w","seqId":"d4d7435b-75ca-962e-17b6-cbc478da83d8"}

解決辦法：將變量 json_decode() 后即可。

例：

// 轉成JSON對象
$test = json_decode($test);

print_r 打印

stdClass Object
(
    [code] => 0
    [data] => stdClass Object
        (
            [isSrvAccount] => 0
        )

    [mccode] => 0
    [errObj] => stdClass Object
        (
        )

    [reqId] => S1B6Mt01w
    [seqId] => d4d7435b-75ca-962e-17b6-cbc478da83d8
)

如果是 curl 方式的話記得設置 CURLOPT_HTTPHEADER

// 設置HTTP頭
curl_setopt ( $curl, CURLOPT_HTTPHEADER, ["Content-Type: application/json"] );