oracle根據身份證號碼 計算年齡、性別

一、Oracle根據身份證判斷性別:
女生身份證:

• 431382198103246985

男生身份證:

• 150921197208173492

SQL語句如下:

select decode(mod (to_number(substr('110228197802199547' ,17, 1)),2 ),0, '女','男' ) as sex from dual ;
 
select decode(mod (to_number(substr('530323197503252610' ,17, 1)),2 ),0, '女','男' ) as sex from dual ;

select decode(mod (to_number(substr('110228197802199547' ,17, 1)),2 ),0, '2','1' ) as sex from dual ;
 
select decode(mod (to_number(substr('530323197503252610' ,17, 1)),2 ),0, '2','1' ) as sex from dual ;

二、Oracle根據身份證計算年齡:

//方法一
select (to_char(sysdate, 'yyyy') - substr('430426199303014475', 7, 4)) age from dual;
//方法二
select trunc(to_number(to_char(sysdate,'yyyymmdd'))/10000 - to_number(to_char(to_date('1982-8-28','yyyy-mm-dd'),'yyyymmdd'))/10000) from dual
//方法三
select trunc((to_char(sysdate,'yyyyMMdd')-to_char(to_date(substr('430426199303014475',7,8),'yyyy-MM-dd'),'yyyyMMdd'))/10000)  from dual;

原文地址：https://www.cnblogs.com/wjxbk/p/9366225.html