windows 下tomcat重啟腳本

@echo off&setlocal enabledelayedexpansion
@rem (start /min cmd.exe /c %0 :&exit)
start /min 
title Tomcat 重啟腳本%1
cd ..\
set CATALINA_HOME=%cd%
set STR_TASK=%1
set JAVA_HOME=%CATALINA_HOME%\bin\jdk1.7.0_55
cd /D %CATALINA_HOME%\bin
call %CATALINA_HOME%\bin\shutdown.bat
ping -n 3 localhost >nul
wmic process where name="java.exe" get processid,commandline |findstr /i %STR_TASK%  >#
for /f "delims=*" %%i in (#) do (      
   set var=%%i
   set var=!var:start= #!
   for /f "tokens=3 delims=#" %%a in ("!var!") do (set tomcatpid=%%a)
)
del # >nul
if defined tomcatpid taskkill /pid !tomcatpid!
ping -n 3 localhost >nul
call %CATALINA_HOME%\bin\startup.bat

taskkill /im cmd.exe

由於windows的任務不好鎖定，所以執行的時候，需要傳入tomcat的主目錄的名稱用來鎖定進程號，保證運行的tomcat中沒有重復的文件名。

下面是我代碼的調用示例

String cmdcommand = "";
            String osname = System.getProperties().getProperty("os.name").toLowerCase();
            File  partfile = new File(new  File(ServerDirUtils.getServerRoot()).getParent());
            String rootdirpath = partfile.getParent();
            String rootname = partfile.getParentFile().getName();
            if(!osname.toLowerCase().contains("windows")){
                String rootPath = rootdirpath +File.separator+"bin"+File.separator+"restart.sh";
                cmdcommand = "sh "+rootPath+   "  "+rootname;
            }else{
                String rootPath = rootdirpath+File.separator+"bin"+File.separator+"restart.bat";
                cmdcommand = "cmd /c start "+rootPath+"  "+rootname;
            }
            logger.error("執行的命令為:"+cmdcommand);
            try {
                Runtime.getRuntime().exec(cmdcommand);
            } catch (IOException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }

如假如我的tomcat的目錄為D:\zhk\apache-tomcat-8.5.39

那命令的組成為：

cmdcommand = "cmd /c start  【你的重啟bat的所在的位置，建議放在bin目錄下】  apache-tomcat-8.5.39