postgres 按正則表達式切割並取值

按照大寫的字母將name切割成兩部分,並獲取第二部分的值

select name, (regexp_split_to_array(name, '[A-Z]') ) [ 2 ]

from stock_location
where name like '%0%';
-- 按照大寫的字母將name切割成兩部分,並獲取第二部分的值

name,regexp_split_to_array
06-1A05,05
06-1A06,06
06-1A01,01
06-1A10,10
06-1A11,11
06-1A12,12
06-1A13,13
06-1A02,02
06-1A03,03
06-1A04,04
06-1A07,07
06-1A08,08