CSS獲取兄弟節點

• css匹配到多個元素獲取兄弟節點

 

1. aui-table-row.aui-table__row:nth-of-type(1)
2. 使用場景一般為同樣的css獲取到多個元素，然后可以通過獲取text等其他

   from selenium import webdriver
   from selenium.webdriver.common.by import By
   
   driver = webdriver.Chrome()
   css_loc = (By.CSS_SELECTOR,"aui-table-row.aui-table__row")
   eles = driver.find_elements(*css_loc)
   css_path=""
   # 通過判斷text，找到對應元素
   for inx, ele in enumerate(eles):
       if ele.text.find("xxx"):
           css_path = "aui-table-row.aui-table__row:nth-of_type({})".format(inx+1)
   
   #獲取到對應元素下面的button
   new_css_loc = (By.CSS_SELECTOR,css_path+" button")
   

   　　

   比對來確定某個元素，從而定位到對應的元素做操作