關於Java錯誤：Exception in thread "main" java.lang.IllegalStateException: No match found的解決方案

public static void main(String[] args) {
        String line = "ABCDEFG666dcab";
        String pattern = "(\\D*)(\\d+)(.*)";
        Pattern r = Pattern.compile(pattern);
        Matcher m = r.matcher(line);
        System.out.println("Found value: " + m.group(0));
        System.out.println("Found value: " + m.group(1));
        System.out.println("Found value: " + m.group(2));
        System.out.println("Found value: " + m.group(3));
}

上述代碼的原本目的是捕獲字符串的三個部分：ABCDEFG,666還有dcba，但是真正運行的時候卻報出了異常

修改成下面的形式即可

public static void main(String[] args){
        String line = "ABCDEFG666dcab";
        String pattern = "(\\D*)(\\d+)(.*)";
        Pattern r = Pattern.compile(pattern);
        Matcher m = r.matcher(line);
        if (m.find( )) {
            System.out.println("Found value: " + m.group(0) );
            System.out.println("Found value: " + m.group(1) );
            System.out.println("Found value: " + m.group(2) );
            System.out.println("Found value: " + m.group(3) );
        } else {
            System.out.println("NO MATCH");
        }
    }

 關於為什么可以這么改，以及find的具體含義，可以看一下我的另一篇隨筆https://www.cnblogs.com/owczhlol/p/12926609.html