最近工作中需要寫一些運營數據報表的頁面,后端返回的數據都是未處理過的json,所以,大量的運算任務交給了前端來做,這其中有一個功能就是對數據進行分組,一開始我自己也嘗試寫了一些,但代碼量比較大,顯得很繁瑣,直到后來在stackoverflow上看到了某位大牛寫的方法,非常簡潔優雅,自己也進行修改簡化。代碼如下:
function groupBy( array , id ) { let groups = {}; array.forEach( function( o ) { let group = JSON.stringify( o[id] ); groups[group] = groups[group] || []; groups[group].push( o ); }); return Object.values(groups); } let name = "name" let list = [ {"name": "John","Average":15,"High":10,"DtmStamp":1358226000000}, {"name": "Jane","Average":16,"High":92,"DtmStamp":1358226000000}, {"name": "Jane","Average":17,"High":45,"DtmStamp":1358226000000}, {"name": "John","Average":18,"High":87,"DtmStamp":1358226000000}, {"name": "Jane","Average":15,"High":10,"DtmStamp":1358226060000}, {"name": "John","Average":16,"High":87,"DtmStamp":1358226060000}, {"name": "John","Average":17,"High":45,"DtmStamp":1358226060000}, {"name": "Jane","Average":18,"High":92,"DtmStamp":1358226060000} ]; let sorted = groupBy(list, name); console.log(sorted);
- 函數groupBy有兩個形參,一為對象數組,二為指定分類方式的key;
- groupBy函數內,先創建一個空對象;
- 然后forEach遍歷對象數組,遍歷時要執行的函數中只有一個形參o(數組中的每個元素);
- 由於下面函數調用是想用name來分組,因此let group = JSON.stringify( f(o) ),相當於先獲取到對象數組list中的name屬性對應的屬性值並放入數組中:["John"],然后再將屬性值轉換為json字符串:'["John"]';
- groups[group] = groups[group] || [],在js中對象也是關聯數組,因此這里相當於做了兩件事,一是把group作為groups的key,二是將對應的value初始化,第一次執行為空數組,循環執行時找到相同的name時保持不變;
- groups[group].push( o ),這句相當於把list中每個對象壓入數組中作為value;
- 最后,Object.values(groups)是取出groups對象中的所有values,返回分好了組的二維數組,至此大功告成~~~
[ [ { name: 'John', Average: 15, High: 10, DtmStamp: 1358226000000 }, { name: 'John', Average: 18, High: 87, DtmStamp: 1358226000000 }, { name: 'John', Average: 16, High: 87, DtmStamp: 1358226060000 }, { name: 'John', Average: 17, High: 45, DtmStamp: 1358226060000 } ], [ { name: 'Jane', Average: 16, High: 92, DtmStamp: 1358226000000 }, { name: 'Jane', Average: 17, High: 45, DtmStamp: 1358226000000 }, { name: 'Jane', Average: 15, High: 10, DtmStamp: 1358226060000 }, { name: 'Jane', Average: 18, High: 92, DtmStamp: 1358226060000 } ] ]