輸入頁碼實現翻頁跳轉

try:
    self.browser.get(request.url)
    if page > 1:
        print(page)
        # input = self.wait.until(EC.presence_of_element_located((By.CSS_SELECTOR, '# J_bottomPage > span.p-skip > input')))
        # input.clear()
        # input.send_keys(page)
        # time.sleep(5)
        '''
        模擬點擊下一頁
        '''
        # fp_next = self.browser.find_element_by_xpath('//*[@id = "J_bottomPage"]/span[1]/a[9]/em')
        # # fp_next = browser.find_element_by_css_selector('a.fp-next')
        # # 點擊下一頁
        # fp_next.click()

        # 將網頁中輸入跳轉頁的輸入框賦值給input變量 EC.presence_of_element_located，判斷輸入框已經被加載出來
        #input = self.wait.until(EC.presence_of_element_located((By.CSS_SELECTOR, '# J_bottomPage > span.p-skip > input')))
        input = self.browser.find_element_by_css_selector('span.p-skip input')
        input.clear()
        input.send_keys(page)
        print('成功輸入頁碼')
        print('************************')
        # 將網頁中調准頁面的確定按鈕賦值給submit變量，EC.element_to_be_clickable 判斷此按鈕是可點擊的
        #submit = self.wait.until(EC.element_to_be_clickable((By.CSS_SELECTOR, '# J_bottomPage > span.p-skip > a')))
        submit = self.browser.find_element_by_css_selector('span.p-skip a')
        submit.click()  # 點擊按鈕
        time.sleep(5)
        print('成功點擊下一頁')
        print('************************')
        time.sleep(15)

        # 判斷當前頁碼出現在了輸入的頁面中，EC.text_to_be_present_in_element 判斷元素在指定字符串中出現
        #self.wait.until(EC.text_to_be_present_in_element((By.CSS_SELECTOR, '#J_bottomPage > span.p-num > a.curr'),str(page)))
        # 等待 #J_goodsList 加載出來，為頁面數據，加載出來之后，在返回網頁源代碼
        #self.wait.until(EC.text_to_be_present_in_element((By.CSS_SELECTOR, '#J_bottomPage > span.p-num > a.curr'),str(page)))
    print(request.url)
    return HtmlResponse(url=request.url, body=self.browser.page_source, request=request, encoding='utf-8',status=200)
except TimeoutException:
    return HtmlResponse(url=request.url, status=500, request=request)