宅在家中無事,刷面試題,發現了一個很有意思的面試題。
就來琢磨一下這個是如何能夠處理成功。(這是一個長更新視頻,說不定中間就干其他的去了,慢慢更ing) StratTime : 202002191600
首先我們來造一下數據。雖然不知道淘寶的購物記錄,但是我們來算成ip瀏覽記錄吧。那么我們來獲取10億條ip
代碼如下
public class createIp { public static String getRandomIp() { // ip范圍 int[][] range = { { 607649792, 608174079 }, // 36.56.0.0-36.63.255.255 { 1038614528, 1039007743 }, // 61.232.0.0-61.237.255.255 { 1783627776, 1784676351 }, // 106.80.0.0-106.95.255.255 { 2035023872, 2035154943 }, // 121.76.0.0-121.77.255.255 { 2078801920, 2079064063 }, // 123.232.0.0-123.235.255.255 { -1950089216, -1948778497 }, // 139.196.0.0-139.215.255.255 { -1425539072, -1425014785 }, // 171.8.0.0-171.15.255.255 { -1236271104, -1235419137 }, // 182.80.0.0-182.92.255.255 { -770113536, -768606209 }, // 210.25.0.0-210.47.255.255 { -569376768, -564133889 }, // 222.16.0.0-222.95.255.255 }; Random rdint = new Random(); int index = rdint.nextInt(10); String ip = num2ip(range[index][0] + new Random().nextInt(range[index][1] - range[index][0])); return ip; } /* * 將十進制轉換成IP地址 */ public static String num2ip(int ip) { int[] b = new int[4]; String x = ""; b[0] = (int) ((ip >> 24) & 0xff); b[1] = (int) ((ip >> 16) & 0xff); b[2] = (int) ((ip >> 8) & 0xff); b[3] = (int) (ip & 0xff); x = Integer.toString(b[0]) + "." + Integer.toString(b[1]) + "." + Integer.toString(b[2]) + "." + Integer.toString(b[3]); return x; }
public class topTenValueMake { public static void main(String[] args) throws IOException{ long startTime = System.currentTimeMillis(); int i ; int j ; String strPath = "D:"+File.separator+"test"+File.separator+"TopTenValue.txt"; File file = new File(strPath); file.createNewFile(); FileWriter fWriter = new FileWriter(file); fWriter.write("開始寫數據"); for(j=1;j<=100000;j++){ StringBuffer sBuffer = new StringBuffer(); for(i=1;i<=10000;i++){ sBuffer.append(createIp.getRandomIp()+","); } fWriter.write(sBuffer.toString()); fWriter.flush(); System.out.println(j*i); } fWriter.close(); long endTime = System.currentTimeMillis(); long time = endTime - startTime; long hour = time/(60*60*1000); long minute = (time - hour*60*60*1000)/(60*1000); long second = (time - hour*60*60*1000 - minute*60*1000)/1000; System.out.println(hour+ "時" + minute + "分 " + second+"秒"); } }
總運行時間
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