從 第3章-8 字符串逆序 開始
1.
n = str(input()) n1=n[::-1] print(n1)
2.
不是很好做這道題，自己還是C語言的思維，網上幾乎也找不到什么答案
s = input() idx = s.find("#") s = s[:idx] ss = s[:idx] s_16 = "0123456789ABCDEFabcdef"
for c in s: if c not in s_16: s = s.replace(c, '') flag = 0 for c in ss: if c in s_16: flag = ss.find(c) break
if '-' in ss[:flag]: s = '-' + s if len(s) == 0: num_10 = 0 else: num_10 = int(s, 16) print(num_10)
3.
濾掉5個字母，還有空格和感嘆號
a=input() count=0 for i in range(0,len(a)): if(a[i]!='A' and a[i]!='E' and a[i]!='I' and a[i]!='O' and a[i]!='U' and a[i]!='!' and a[i]!=' ' and 'A'<=a[i]<='Z'): count=count+1
print(count)
4.
我還在思考字符串怎么排序，發現其實之前做過的sort()函數可以用來無差別排序，一下子就簡單了：
ls =list(input().split()) ls1=sorted(ls) print("After sorted") for i in ls1: print(i)