用二維數組輸出一個10行的楊輝三角:
1
11
121
1331
14641
.......
通過觀察,不難得到對於楊輝三角中,每行的首,末位元素均為1,而中間的元素yangHui[i][j]=yangHui[i-1][j-1]+yangHui[i-1][j]
所以可以先建立一個二維數組,再按照這種規律依次賦值,最后遍歷一遍即可
public class yangHuiTriangle {
public static void main(String[] args) {
//聲明並初始化二維數組;
int[][] yangHui = new int[10][];
for (int i = 0; i < yangHui.length; i++) {
yangHui[i] = new int[i + 1];
}
//給二維數組賦值
for (int i = 0; i < yangHui.length; i++) {
//先給邊上的賦值
yangHui[i][0] = 1;
yangHui[i][i] = 1;
//再給中間的賦值
for (int j = 1; j < yangHui[i].length - 1; j++) {
yangHui[i][j] = yangHui[i - 1][j - 1] + yangHui[i - 1][j];
}
}
//遍歷二維數組
for (int i = 0; i < yangHui.length; i++) {
for (int j = 0; j < yangHui[i].length; j++) {
System.out.print(yangHui[i][j] + " ");
}
System.out.println();
}
}
}