postgresql 兩行數據時間之差


//獲取兩行之間的時間差,並轉換成分鍾

1 select *,extract(epoch from((aaa."ar"::timestamp) - (bbb."br"::timestamp)))/60 as counterDiffer from 
2 (select row_number() OVER (ORDER BY "ID") as aa,"ReceiveTime" as ar from public."YourTableName" where "searchID" = '123456') as aaa,
3 (select row_number() OVER (ORDER BY "ID") as bb,"ReceiveTime" as br from public."YourTableName" where "searchID" = '123456') as bbb 4 where aa -1 =bb order by ar

 


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