lag和lead VS shift
該函數的格式如下:
- 第一個參數為列名,
- 第二個參數為往上第n行(可選,默認為1),
- 第三個參數為默認值(當往上第n行為NULL時候,取默認值,如不指定,則為NULL)
lag
lag(字段名,N,默認值) over(partition by 分組字段 order by 排序字段 排序方式)
lead
lead(字段名,N,默認值) over(partition by 分組字段 order by 排序字段 排序方式)
案例:
select cookieid, createtime, url, row_number() over (partition by cookieid order by createtime) as rn, LAG(createtime,1,'1970-01-01 00:00:00') over (partition by cookieid order by createtime) as last_1_time, LAG(createtime,2) over (partition by cookieid order by createtime) as last_2_time from cookie.cookie4

select cookieid, createtime, url, row_number() over (partition by cookieid order by createtime) as rn, LEAD(createtime,1,'1970-01-01 00:00:00') over (partition by cookieid order by createtime) as next_1_time, LEAD(createtime,2) over (partition by cookieid order by createtime) as next_2_time from cookie.cookie4;

窗口函數的pandas實現
pandas中使用shift函數來實現lag/lead函數
import pandas as pd df=pd.read_csv('c:/Users/WQBin/Desktop/data.csv',engine='python', names=['cookieid','createtime','url']) df['last_url'] = df.sort_values('createtime').groupby('cookieid')['url'].shift(1) df['next_url'] = df.sort_values('createtime').groupby('cookieid')['url'].shift(-1) df.sort_values(by=['cookieid','createtime'])

first_value和 last_value VS first()和last()
- FIRST_VALUE 返回組中數據窗口的第一個值
- FIRST_VALUE ( [scalar_expression )OVER ( [ partition_by_clause ] order_by_clause )
- LAST_VALUE 返回組中數據窗口的最后一個值
- LAST_VALUE ( [scalar_expression )OVER ( [ partition_by_clause order_by_clause )
select cookieid, createtime, url, row_number() over (partition by cookieid order by createtime) as rn, first_value(url) over (partition by cookieid order by createtime) as first1 from cookie.cookie4;

select cookieid, createtime, url, row_number() over (partition by cookieid order by createtime) as rn, last_value(url) over (partition by cookieid order by createtime) as last1 from cookie.cookie4;

窗口函數的pandas實現

df.sort_values(['createtime'], ascending=[ 1]).groupby(['cookieid']).first()

df.sort_values(['createtime'], ascending=[ 1]).groupby(['cookieid']).last()

