題目如下:
Given an array of strings
products
and a stringsearchWord
. We want to design a system that suggests at most three product names fromproducts
after each character ofsearchWord
is typed. Suggested products should have common prefix with the searchWord. If there are more than three products with a common prefix return the three lexicographically minimums products.Return list of lists of the suggested
products
after each character ofsearchWord
is typed.Example 1:
Input: products = ["mobile","mouse","moneypot","monitor","mousepad"], searchWord = "mouse" Output: [ ["mobile","moneypot","monitor"], ["mobile","moneypot","monitor"], ["mouse","mousepad"], ["mouse","mousepad"], ["mouse","mousepad"] ] Explanation: products sorted lexicographically = ["mobile","moneypot","monitor","mouse","mousepad"] After typing m and mo all products match and we show user ["mobile","moneypot","monitor"] After typing mou, mous and mouse the system suggests ["mouse","mousepad"]Example 2:
Input: products = ["havana"], searchWord = "havana" Output: [["havana"],["havana"],["havana"],["havana"],["havana"],["havana"]]Example 3:
Input: products = ["bags","baggage","banner","box","cloths"], searchWord = "bags" Output: [["baggage","bags","banner"],["baggage","bags","banner"],["baggage","bags"],["bags"]]Example 4:
Input: products = ["havana"], searchWord = "tatiana" Output: [[],[],[],[],[],[],[]]Constraints:
1 <= products.length <= 1000
1 <= Σ products[i].length <= 2 * 10^4
- All characters of
products[i]
are lower-case English letters.1 <= searchWord.length <= 1000
- All characters of
searchWord
are lower-case English letters.
解題思路:首先對products排序,接下來把每個product存入字典樹中,字典樹每個節點除了保存子節點的地址之外,還存前三個前綴能映射到該節點的product。
代碼如下:
class TreeNode(object): def __init__(self,val): self.val = val self.child = {} self.top3 = [] class Trie(object): def __init__(self): self.root = TreeNode(None) def add(self,word): node = self.root for i in word: if i not in node.child: child_node = TreeNode(i) node.child[i] = child_node if len(node.top3) < 3: node.top3.append(word) node = node.child[i] if len(node.top3) < 3: node.top3.append(word) def search(self,prefix): node = self.root for i in prefix: if i not in node.child: return [] node = node.child[i] return node.top3 class Solution(object): def suggestedProducts(self, products, searchWord): """ :type products: List[str] :type searchWord: str :rtype: List[List[str]] """ products.sort() trie = Trie() for product in products: trie.add(product) res = [] word = '' for char in searchWord: word += char res.append(trie.search(word)) return res