文章非個人原創,內容copy自:[易百教程]https://www.yiibai.com/java_xml/java_xpath_parser.html
XPath是萬維網聯盟(W3C)的官方推薦。它定義了一個語言在XML文件中查找信息。它被用於遍歷XML文檔的元素和屬性。 XPath提供各種類型,可用於從XML文檔查詢相關的信息表現形式。
XPath使用步驟
1.導入XML相關的軟件包
import org.w3c.dom.*; import org.xml.sax.*; import javax.xml.parsers.*; import javax.xml.xpath.*; import java.io.*;
2.創建DocumentBuilder
DocumentBuilderFactory factory =
DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
3.從文件或數據流創建一個文檔
StringBuilder xmlStringBuilder = new StringBuilder(); xmlStringBuilder.append("<?xml version="1.0"?> <class> </class>"); ByteArrayInputStream input = new ByteArrayInputStream( xmlStringBuilder.toString().getBytes("UTF-8")); Document doc = builder.parse(input);
4.創建XPath對象
XPath xPath = XPathFactory.newInstance().newXPath();
5.編譯XPath表達式使用XPath.compile() ,並由XPath.evaluate()評估計算獲得一個節點列表
String expression = "/class/student";
NodeList nodeList = (NodeList) xPath.compile(expression).evaluate(doc, XPathConstants.NODESET);
6.遍歷節點列表。
for (int i = 0; i < nodeList.getLength(); i++) { Node nNode = nodeList.item(i); ... }
7.檢查屬性
//returns specific attribute getAttribute("attributeName"); //returns a Map (table) of names/values getAttributes();
8.檢查子元素
//returns a list of subelements of specified name getElementsByTagName("subelementName"); //returns a list of all child nodes getChildNodes();
demo案例
xml.txt
<?xml version="1.0"?> <class> <student rollno="393"> <firstname>dinkar</firstname> <lastname>kad</lastname> <nickname>dinkar</nickname> <marks>85</marks> </student> <student rollno="493"> <firstname>Vaneet</firstname> <lastname>Gupta</lastname> <nickname>vinni</nickname> <marks>95</marks> </student> <student rollno="593"> <firstname>jasvir</firstname> <lastname>singh</lastname> <nickname>jazz</nickname> <marks>90</marks> </student> </class>
XPathParserDemo.java
import java.io.File; import java.io.IOException; import javax.xml.parsers.DocumentBuilderFactory; import javax.xml.parsers.DocumentBuilder; import javax.xml.parsers.ParserConfigurationException; import javax.xml.xpath.XPath; import javax.xml.xpath.XPathConstants; import javax.xml.xpath.XPathExpressionException; import javax.xml.xpath.XPathFactory; import org.w3c.dom.Document; import org.w3c.dom.NodeList; import org.w3c.dom.Node; import org.w3c.dom.Element; import org.xml.sax.SAXException; public class XPathParserDemo { public static void main(String[] args) { try { File inputFile = new File("./xml.txt"); DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance(); DocumentBuilder dBuilder; dBuilder = dbFactory.newDocumentBuilder(); Document doc = dBuilder.parse(inputFile); doc.getDocumentElement().normalize(); XPath xPath = XPathFactory.newInstance().newXPath(); String expression = "/class/student"; NodeList nodeList = (NodeList) xPath.compile(expression).evaluate(doc, XPathConstants.NODESET); for (int i = 0; i < nodeList.getLength(); i++) { Node nNode = nodeList.item(i); System.out.println("\nCurrent Element :" + nNode.getNodeName()); if (nNode.getNodeType() == Node.ELEMENT_NODE) { Element eElement = (Element) nNode; System.out.println("Student roll no : " + eElement.getAttribute("rollno")); System.out.println("First Name : " + eElement .getElementsByTagName("firstname") .item(0) .getTextContent()); System.out.println("Last Name : " + eElement .getElementsByTagName("lastname") .item(0) .getTextContent()); System.out.println("Nick Name : " + eElement .getElementsByTagName("nickname") .item(0) .getTextContent()); System.out.println("Marks : " + eElement .getElementsByTagName("marks") .item(0) .getTextContent()); } } } catch (ParserConfigurationException e) { e.printStackTrace(); } catch (SAXException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } catch (XPathExpressionException e) { e.printStackTrace(); } } }
執行的結果:
Current Element :student
Student roll no : 393
First Name : dinkar
Last Name : kad
Nick Name : dinkar
Marks : 85
Current Element :student
Student roll no : 493
First Name : Vaneet
Last Name : Gupta
Nick Name : vinni
Marks : 95
Current Element :student
Student roll no : 593
First Name : jasvir
Last Name : singh
Nick Name : jazz
Marks : 90