Flutter json轉換Map

var map = {
      "name": "zhangsan",
      "email": "[e-mail]",
      "age": 1
    };

    //轉成字符串
    String name = json.encode(map);
    print(name);

    //解析字符串
    Map<String, dynamic> user = json.decode(name);
    print("姓名：${user['name']}");
    print("郵箱：${user['email']}");
    print("年齡：${user['age']}");
  }

或者第二種

第二種：內置json創建model方式解析。
先建立model，
class User {
  String name;
  String email;
  int age;

  User(this.name, this.email, this.age) {}

  User.fromJson(Map<String, dynamic>json)
      :name=json["name"],
        email = json["email"],
        age = json["age"];

  Map<String, dynamic> toJson() {
    return {
      "name": name,
      "email": email,
      "age": age
    };
  }
}
然后可以使用了，
var map = {
      "name": "zhangsan",
      "email": "[e-mail]",
      "age": 1
    };

    var user = User.fromJson(map);
    print("name:${user.name}");

    var userMap = User("lisi", "[e-mail]", 3).toJson();
    for (var key in userMap.keys) {
      print("${key} : ${userMap[key]}");
    }
這種是比較常用的用來解析復雜的json

從https://www.cnblogs.com/wupeng88/p/10770135.html轉載

感謝大佬