INSERT INTO test_postgre(id,name,InputTime,age)
VALUES('1','postgre','2018-01-10 22:00:00',24)
ON conflict(id)
DO UPDATE SET name = 'postgreOk', InputTime ='2018-02-22 12:00:00'
來自：https://blog.csdn.net/likawei1314/article/details/79029145?utm_source=blogxgwz2