const char *轉化為char *的方法

直接將const char *賦值給char *是錯誤的，編譯器不允許這種操作。

#include "stdio.h"
#include "string.h"
int main()
{
    //方式1 strcpy
    //方式1.1
    //const char *cpCh = "const char";
    //char ch[64]={0};
    //char *pCh = ch;　　//是不是畫蛇添足啊??
    //strcpy(pCh, cpCh);

    //方式1.2
    const char *cpCh = "const char";
    int nLen = strlen(cpCh);
    char *pCh = new char[nLen + 1];
    strcpy(pCh, cpCh);


    //方式2 const_cast<>()
    //const char *cpCh = "const char";
    //char *pCh = const_cast<char *>(cpCh);//DO not forget '()'
    

    printf("%s", pCh);
    return 0;
}