linux系統使用grep命令提取文件的基名或者路徑名

效果等於~]#dirname /etc/sysconfig/network-scripts/ifcfg-ens33
echo "/etc/sysconfig/network-scripts/ifcfg-ens33"|grep  -o -E "(^/([^/]+/)*[^[:space:]])|^/"|grep -o -E "^/([^/]+/)*"|grep -o -E "(/[^/]+)+|^/"

 

效果等於：~]#basename /etc/sysconfig/network-scripts/ifcfg-ens33
echo "/etc/sysconfig/network-scripts/ifcfg-ens33"|grep  -o -E "[^/]+/?$"|grep -o -E "^[^/]+"