數字轉人民幣大寫-python實現

 # 算法說明：要求字符串輸入，現將字符串差費為整數部分和小數部分生成list[整數部分,小數部分]

# 將整數部分拆分為：[億，萬，仟]三組字符串組成的List:['0000','0000','0000']（根據實際輸入生成階梯List）
# 例如：600190000010.70整數部分拆分為：['600','1900','0010']
# 然后對list中每個字符串分組進行大寫化再合並
# 最后處理小數部分的大寫化

class Cnumber:
    cdict = {}
    gdict = {}
    xdict = {}

    def __init__(self):
        self.cdict = {1: u'', 2: u'拾', 3: u'佰', 4: u'仟'}
        self.xdict = {1: u'元', 2: u'萬', 3: u'億', 4: u'兆'}  # 數字標識符
        self.gdict = {0: u'零', 1: u'壹', 2: u'貳', 3: u'叄', 4: u'肆', 5: u'伍', 6: u'陸', 7: u'柒', 8: u'捌', 9: u'玖'}

    @staticmethod
    def csplit(cdata):  # 拆分函數，將整數字符串拆分成[億，萬，仟]的list
        g = len(cdata) % 4
        csdata = []
        lx = len(cdata) - 1
        if g > 0:
            csdata.append(cdata[0:g])
        k = g
        while k <= lx:
            csdata.append(cdata[k:k + 4])
            k += 4
        return csdata

    def cschange(self, cki):  # 對[億，萬，仟]的list中每個字符串分組進行大寫化再合並
        lenki = len(cki)

        lk = lenki
        chk = u''
        for i in range(lenki):
            if int(cki[i]) == 0:
                if i < lenki - 1:
                    if int(cki[i + 1]) != 0:
                        chk = chk + self.gdict[int(cki[i])]
            else:
                chk = chk + self.gdict[int(cki[i])] + self.cdict[lk]
            lk -= 1
        return chk

    def cwchange(self, data):
        cdata = str(data).split('.')

        cki = cdata[0]
        ckj = cdata[1]

        chk = u''
        cski = self.csplit(cki)  # 分解字符數組[億，萬，仟]三組List:['0000','0000','0000']
        ikl = len(cski)  # 獲取拆分后的List長度
        # 大寫合並
        for i in range(ikl):
            if self.cschange(cski[i]) == '':  # 有可能一個字符串全是0的情況
                chk = chk + self.cschange(cski[i])  # 此時不需要將數字標識符引入
            else:
                chk = chk + self.cschange(cski[i]) + self.xdict[ikl - i]  # 合並：前字符串大寫+當前字符串大寫+標識符
        # 處理小數部分
        lenkj = len(ckj)
        if lenkj == 1:  # 若小數只有1位
            if int(ckj[0]) == 0:
                chk = chk + u'整'
            else:
                chk = chk + self.gdict[int(ckj[0])] + u'角整'
        else:  # 若小數有兩位的四種情況
            if int(ckj[0]) == 0 and int(ckj[1]) != 0:
                chk = chk + u'零' + self.gdict[int(ckj[1])] + u'分'
            elif int(ckj[0]) == 0 and int(ckj[1]) == 0:
                chk = chk + u'整'
            elif int(ckj[0]) != 0 and int(ckj[1]) != 0:
                chk = chk + self.gdict[int(ckj[0])] + u'角' + self.gdict[int(ckj[1])] + u'分'
            else:
                chk = chk + self.gdict[int(ckj[0])] + u'角整'
        return chk


if __name__ == '__main__':
    pt = Cnumber()
    print(pt.cwchange('600190101000.08'))