題目21:查詢男生、女生人數
這個題目我寫出的sql 還是比較原始的,查詢了3次,這樣的話性能會比較差
SELECT c.a,d.b FROM (SELECT COUNT(*) AS a FROM student WHERE sex like '女')c, (SELECT COUNT(*) AS b FROM student WHERE sex like '男')d
其實還有一種比較簡單的寫法:
SELECT student.sex,COUNT(*) FROM student GROUP BY sex
題目22:查詢名字中含有「風」字的學生信息
SELECT * FROM student WHERE student.stdentname LIKE "%風%"