1.查詢重復值:
select code,count(*) as count from hospital group by code having count>1;
該語句查詢code重復值大於1的記錄
2.刪除重復:
DELETE FROM hospital WHERE id NOT IN (SELECT dt.minno FROM (SELECT MIN(id) AS minno FROM hospital GROUP BY code) dt);
該語句保留id最小的記錄,其余code重復的記錄全部刪除