JavaScript實現方法
document.onkeydown = function(e) { if (!e) e = window.event;//火狐中是 window.event if ((e.keyCode || e.which) == 13) { document.getElementById("loginButtonId").click(); //loginButtonId為button登錄按鈕的ID } }
jQuery實現方法
$(window).keydown(function(e){ var curKey = e.which; if(curKey == 13){ $('#loginFormId').submit(); //loginFormId為form表單的ID } })
轉自https://blog.csdn.net/itmyhome1990/article/details/47381561