一、參考解法：
|
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
|
s
=
input
(
'請輸入字符串：'
)
dic
=
{
'letter'
:
0
,
'integer'
:
0
,
'space'
:
0
,
'other'
:
0
}
for
i
in
s:
if
i >
'a'
and
i<
'z'
or
i>
'A'
and
i<
'Z'
:
dic[
'letter'
]
+
=
1
elif
i
in
'0123456789'
:
dic[
'integer'
]
+
=
1
elif
i
=
=
' '
:
dic[
'space'
]
+
=
1
else
:
dic[
'other'
]
+
=
1
print
(
'統計字符串：'
,s)
print
(dic)
print
(
'------------顯示結果2---------------'
)
for
i
in
dic:
print
(
'%s='
%
i,dic[i])
print
(
'------------顯示結果3---------------'
)
for
key,value
in
dic.items():
print
(
'%s='
%
key,value)
|
二、參考解法：
|
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
|
tmpStr
=
input
(
'請輸入字符串：'
)
alphaNum
=
0
numbers
=
0
spaceNum
=
0
otherNum
=
0
for
i
in
tmpStr:
if
i.isalpha():
alphaNum
+
=
1
elif
i.isnumeric():
numbers
+
=
1
elif
i.isspace():
spaceNum
+
=
1
else
:
otherNum
+
=
1
print
(
'字母=%d'
%
alphaNum)
print
(
'數字=%d'
%
numbers)
print
(
'空格=%d'
%
spaceNum)
print
(
'其他=%d'
%
otherNum)
|
三、參考解法：
|
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
|
InPut
=
input
(
'請輸入字符串：'
)
letters
=
[ ]
spaces
=
[ ]
digits
=
[ ]
others
=
[ ]
for
i
in
iter
(
InPut
):
if
i.isalpha():
letters.append(i)
elif
i.isspace():
spaces.append(i)
elif
i.isdigit():
digits.append(i)
else
:
others.append(i)
print
(
'''
字母: {}, 個數: {}
空格: {}, 個數: {}
數字: {}, 個數: {}
其他: {}, 個數: {}'''
\
.
format
(letters,
len
(letters), spaces,
len
(spaces), digits,
len
(digits),others,
len
(others)))
|
四、參考解法：
使用正則表達式 re.findall()
import re s = input('請輸入一串字符：') char=re.findall(r'[a-zA-Z]',s)#以列表類型返回全部能匹配的子串 num=re.findall(r'[0-9]',s) blank=re.findall(r' ',s) chi=re.findall(r'[\u4E00-\u9FFF]',s)#漢字的Unicode編碼范圍 other = len(s)-len(char)-len(num)-len(blank)-len(chi) print('字母',len(char),'\n數字',len(num),'\n空格',len(blank),'\n中文',len(chi),'\n其他',other)
五、參考解法：
使用正則表達式 re.match()
|
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
|
import re
def splitFunc( ):
tmpStr = input(
'請輸入字符串：'
)
charNum = 0
digNum = 0
spaceNum = 0
otherNum = 0
for
i
in
range(len(tmpStr)):
if
re.match(
'[a-zA-Z]'
,tmpStr[i]):
charNum +=1
elif re.match(
'\d'
,tmpStr[i]):
digNum +=1
elif re.match(
'\s'
,tmpStr[i]):
spaceNum +=1
else
:
otherNum +=1
print(
'字符：'
,charNum)
print(
'數字：'
,digNum)
print(
'空格：'
,spaceNum)
print(
'其他：'
,otherNum)
splitFunc()
|