創建如下表數據
select * from t1 ;
select * from t2;
現需求:參照T2表,修改T1表,修改條件為兩表的fname列內容一致。
方式1,update
常見陷阱:
UPDATE T1 SET T1.FMONEY = (select T2.FMONEY from t2 where T2.FNAME = T1.FNAME)
執行后T1結果如下:
有一行原有值,被更新成空值了。
正確寫法:
UPDATE T1 SET T1.FMONEY = (select T2.FMONEY from t2 where T2.FNAME = T1.FNAME) WHERE EXISTS(SELECT 1 FROM T2 WHERE T2.FNAME = T1.FNAME);
方式2:內聯視圖更新
UPDATE ( select t1.fmoney fmoney1,t2.fmoney fmoney2 from t1,t2 where t1.fname = t2.fname )t set fmoney1 =fmoney2;
方式3:merge更新
merge into t1 using (select t2.fname,t2.fmoney from t2) t on (t.fname = t1.fname) when matched then update set t1.fmoney = t.fmoney;