需求:
最近搞報表的項目,要寫數據庫sql語句,根據狀態值查詢狀態的個數,這個開始難為到我了,不過已經有解決辦法了。
在數據庫表中有一個字段是狀態(zt),這里面有1-7這7個狀態,現在查詢每個狀態的數量,並且顯示在一張表中。
正常情況下查狀態是:
SELECT COUNT(*) draft FROM `it_project_info` WHERE `it_project_info`.item_status`='1'; SELECT COUNT(*) checks FROM `it_project_info` WHERE `it_project_info`.item_status`='2'; SELECT COUNT(*) plan FROM `it_project_info` WHERE `it_project_info`.item_status`='3'; SELECT COUNT(*) implement FROM `it_project_info` WHERE `it_project_info`.item_status`='4'; SELECT COUNT(*) online FROM `it_project_info` WHERE `it_project_info`.item_status`='5'; SELECT COUNT(*) cancel FROM `it_project_info` WHERE `it_project_info`.item_status`='6'; SELECT COUNT(*) knot FROM `it_project_info` WHERE `it_project_info`.item_status`='7';
首先,要先將行變成列:
SELECT t.*, CASE WHEN t.`item_status`=1 THEN 1 ELSE 0 END AS draft, CASE WHEN t.`item_status`=2 THEN 1 ELSE 0 END AS checks, CASE WHEN t.`item_status`=3 THEN 1 ELSE 0 END AS plan, CASE WHEN t.`item_status`=4 THEN 1 ELSE 0 END AS implement, CASE WHEN t.`item_status`=5 THEN 1 ELSE 0 END AS online, CASE WHEN t.`item_status`=6 THEN 1 ELSE 0 END AS cancel, CASE WHEN t.`item_status`=7 THEN 1 ELSE 0 END AS knot FROM `it_project_info` t
然后查詢每一列的個數:
SELECT IFNULL(SUM(m.draft), 0) draftTotal, IFNULL(SUM(m.checks), 0) checkTotal, IFNULL(SUM(m.plan), 0) planTotal, IFNULL(SUM(m.implement), 0) implementTotal, IFNULL(SUM(m.online), 0) onlineTotal, IFNULL(SUM(m.cancel), 0) cancelTotal, IFNULL(SUM(m.knot), 0) knotTotal FROM ( SELECT CASE WHEN t.`item_status`=1 THEN 1 ELSE 0 END AS draft, CASE WHEN t.`item_status`=2 THEN 1 ELSE 0 END AS checks, CASE WHEN t.`item_status`=3 THEN 1 ELSE 0 END AS plan, CASE WHEN t.`item_status`=4 THEN 1 ELSE 0 END AS implement, CASE WHEN t.`item_status`=5 THEN 1 ELSE 0 END AS online, CASE WHEN t.`item_status`=6 THEN 1 ELSE 0 END AS cancel, CASE WHEN t.`item_status`=7 THEN 1 ELSE 0 END AS knot FROM `it_project_info` t ) m
這樣就可以得到想要的結果了。